Question 13080 of 790 · California General Electrician Exam
What is the total cross-sectional area of six 10 AWG THHN (0.0211 sq in each) and three 8 AWG THHN (0.0366 sq in each) conductors?
Exactly one answer is correct.
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Correct answer to question 13080
- D: 0.2364 sq in
Explanation
6 x 0.0211 = 0.1266 and 3 x 0.0366 = 0.1098, for a total of 0.2364 sq in. Swapping the areas (6 x 0.0366 plus 3 x 0.0211) gives 0.2829 sq in, and adding just one of each conductor gives 0.0577 sq in.
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